Jesse,

It doesn't give a coordinate transformation, it gives an explanation. 
Shortly I'll post a longer analysis...

Best,
Edgar

On Thursday, February 6, 2014 7:01:11 PM UTC-5, jessem wrote:
>
>
>
> On Thu, Feb 6, 2014 at 6:05 PM, Edgar L. Owen <[email protected]<javascript:>
> > wrote:
>
>> Jesse,
>>
>> OK, here's another question to get to the crux.
>>
>> You claim the twins "meet in the same point of spacetime".
>>
>> OK, if that's a real point in spacetime it MUST have a t-coordinate. What 
>> is the value of that t-coordinate?
>>
>
> In my example it was t=50. But it depends entirely on details like when 
> you set the coordinate clocks to 0, what coordinates the twins departed at, 
> and their respective velocities in this coordinate system.
>
>  
>
>> And what's the relation of that t-coordinate to the different clock time 
>> t-coordinates of the twins? What's the transform that converts the two 
>> different clock time t values to the SAME same point t value?
>>
>
> Why is there a need for one? If two different measuring tapes cross at a 
> point in space, with and the point where they cross is at the 30 cm mark on 
> one tape and the 40 cm mark on the other, and there's a Cartesian 
> coordinate grid on the surface under them which says this point has an 
> x-coordinate of 50, is there a need for a "transformation" that changes 30 
> and 40 to 50?
>  
>
>>
>> I say there isn't any, that relativity can't supply one. And that this 
>> means that, while relativity can arbitrarily DEFINE a same moment in 
>> spacetime as you do, it can NOT explain or calculate it.
>>
>> Only my p-time theory does this, relativity doesn't....
>>
>
> You're saying your p-time theory gives a *mathematical* transformation, or 
> just some sort of "conceptual" transformation? If mathematical, can you 
> give a specific numerical example showing how it works, and what the 
> transformation function is?
>
> Jesse
>

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