On Thu, Feb 6, 2014 at 6:05 PM, Edgar L. Owen <[email protected]> wrote:
> Jesse, > > OK, here's another question to get to the crux. > > You claim the twins "meet in the same point of spacetime". > > OK, if that's a real point in spacetime it MUST have a t-coordinate. What > is the value of that t-coordinate? > In my example it was t=50. But it depends entirely on details like when you set the coordinate clocks to 0, what coordinates the twins departed at, and their respective velocities in this coordinate system. > And what's the relation of that t-coordinate to the different clock time > t-coordinates of the twins? What's the transform that converts the two > different clock time t values to the SAME same point t value? > Why is there a need for one? If two different measuring tapes cross at a point in space, with and the point where they cross is at the 30 cm mark on one tape and the 40 cm mark on the other, and there's a Cartesian coordinate grid on the surface under them which says this point has an x-coordinate of 50, is there a need for a "transformation" that changes 30 and 40 to 50? > > I say there isn't any, that relativity can't supply one. And that this > means that, while relativity can arbitrarily DEFINE a same moment in > spacetime as you do, it can NOT explain or calculate it. > > Only my p-time theory does this, relativity doesn't.... > You're saying your p-time theory gives a *mathematical* transformation, or just some sort of "conceptual" transformation? If mathematical, can you give a specific numerical example showing how it works, and what the transformation function is? Jesse -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
