On Sat, Feb 01, 2014 at 03:46:37PM -0800, Edgar L. Owen wrote: > c. Therefore during the trip there must always be a one to one > correspondence between those actual present moments even though the clock > times are not in synch. Because they both begin and end in that present > moment and never leave it during the trip.
It is here that your argument breaks down. Yes, there is a 1:1 correspondence (a bijection in fact) between the two clock times. But there are many possible such bijections, where you (implicitly) assume only a single one (perhaps the linear one). In SR there is a differnt bijection for each different inertial reference frame. -- ---------------------------------------------------------------------------- Prof Russell Standish Phone 0425 253119 (mobile) Principal, High Performance Coders Visiting Professor of Mathematics [email protected] University of New South Wales http://www.hpcoders.com.au ---------------------------------------------------------------------------- -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
