On 9/4/2025 8:10 PM, Alan Grayson wrote:
On Thursday, September 4, 2025 at 6:54:57 PM UTC-6 Brent Meeker wrote:
On 9/4/2025 6:24 AM, Alan Grayson wrote:
On Thursday, September 4, 2025 at 4:38:50 AM UTC-6 John Clark wrote:
On Wed, Sep 3, 2025 at 6:53 PM Alan Grayson
<[email protected]> wrote:
*>> |E|^2 gives the _relative_ probabilities of
detecting aphoton at different pointson the screen,
it gives you the correct curve shape butisnot
normalizedso all the probabilities don't add up to
exactly one. To make it a true probability
distribution that integrates to 1 you divide |E|^2 by
a constant,the total integrated intensity across the
screen.*
/> But this E is the classical energy, and when the EM
field is quantized don't we need a huge number of photons
to define the curve you reference above?/
*If you are able to calculatethe probability distribution for
where a singlephoton is likely to deliver its quantum of
energyafter passing through two slits, then you will be able
to calculate how the energy will be distributed across the
entire screen for any finite number of photons that passes
through those two slits.*
/> Is there a differential equation that when solved,
gives us the wf of a RELATIVISTIC particle?/
*If you start with Maxwell's Equations then you get that
automaticallybecause, although they were discovered a decade
before Einstein was born, they are 100% compatible with both
Special and General Relativity. Interestingly they are _NOT_
compatible with Newtonian physics because Newton claimed that
all speed was relative, but Maxwell's Equations can produce
an absolute speed, the speed of light, and there are no
specifications about who should observe that speed, so
everybody must. Resolving that inconsistency was the
motivation Einstein had for developing relativity; he made no
changes to Maxwell's Equations, he thought they were fine
just as they are, instead he modified Newtonian physics. *
*But ME's describe the behavior of the EM field, not the
relativistic behavior of a particle. So I pose my question above
again. TY, AG*
They also describe the energy propagation of the EM field. And
given the known energy per photon that implies the probability
distribution of the photons.
> /Is there an equation that gives the wf of a photon? TY, AG /
*As I explained before, the electromagnetic field amplitude
can take on the role of a photon’s probability amplitude.*
*But this is within the context of the double slit experiment. If
there is a wf for a photon, it should be, I think, independent of
any experimental set up. AG *
No, it is *not* only in the context of the double slit
experiment. The context of the double slit experiment is supplied
by initial conditions.
Brent
*What initial conditions could yield a similar result that we get for
a free non-relativistic particle; namely, that the wf spreads over
time so its position probability becomes progressively uncertain? *
The initial condition that the wave function is spherically symmetric.
*So No, I don't agree that applying the double slit will yield a wf *
The double slit doesn't "yield a wf". It implies an initial condition*
*
*for a photon which supports a similar result as in the case just
mentioned. And I am beginning to suspect that we have no equation, the
solution of which gives us the wf of a RELATIVISTIC particle, or a
PHOTON. If such equations exist, plesae post them. TY, AG*
You want me to waste 15m typing in a lot of display math just so you can
see a bunch of equations? Go look'em up.
Brent
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