On 9/4/2025 6:24 AM, Alan Grayson wrote:
On Thursday, September 4, 2025 at 4:38:50 AM UTC-6 John Clark wrote:
On Wed, Sep 3, 2025 at 6:53 PM Alan Grayson <[email protected]>
wrote:
*>> |E|^2 gives the _relative_ probabilities of detecting
aphoton at different pointson the screen, it gives you the
correct curve shape butisnot normalizedso all the
probabilities don't add up to exactly one. To make it a
true probability distribution that integrates to 1 you
divide |E|^2 by a constant,the total integrated intensity
across the screen.*
/> But this E is the classical energy, and when the EM field
is quantized don't we need a huge number of photons to define
the curve you reference above?/
*If you are able to calculatethe probability distribution for
where a singlephoton is likely to deliver its quantum of
energyafter passing through two slits, then you will be able to
calculate how the energy will be distributed across the entire
screen for any finite number of photons that passes through those
two slits.*
/> Is there a differential equation that when solved, gives us
the wf of a RELATIVISTIC particle?/
*If you start with Maxwell's Equations then you get that
automaticallybecause, although they were discovered a decade
before Einstein was born, they are 100% compatible with both
Special and General Relativity. Interestingly they are _NOT_
compatible with Newtonian physics because Newton claimed that all
speed was relative, but Maxwell's Equations can produce an
absolute speed, the speed of light, and there are no
specifications about who should observe that speed, so everybody
must. Resolving that inconsistency was the motivation Einstein
had for developing relativity; he made no changes to Maxwell's
Equations, he thought they were fine just as they are, instead he
modified Newtonian physics. *
*But ME's describe the behavior of the EM field, not the relativistic
behavior of a particle. So I pose my question above again. TY, AG*
They also describe the energy propagation of the EM field. And given
the known energy per photon that implies the probability distribution of
the photons.
**
> /Is there an equation that gives the wf of a photon? TY, AG /
*As I explained before,the electromagneticfield amplitude can
take on the role of a photon’s probability amplitude.*
*But this is within the context of the double slit experiment. If
there is a wf for a photon, it should be, I think, independent of any
experimental set up. AG *
No, it is *not* only in the context of the double slit experiment. The
context of the double slit experiment is supplied by initial conditions.
Brent
*John K Clark See what's on my new list at Extropolis
<https://groups.google.com/g/extropolis>*
ijt
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