On Thursday, June 19, 2025 at 5:38:47 AM UTC-6 John Clark wrote:

On Thu, Jun 19, 2025 at 1:47 AM Alan Grayson <[email protected]> wrote:

*>>> I gave the example of the SS orbiting the Earth. AG*


*>> And as I explained in another post that you evidently have not bothered 
to read: *


*> Evidently?  I indeed read it and I pointed out your error, which you 
completely forgot and correctly below. AG*


*Where is the error in the below?  *


This is getting retarded. What you have below is correct. What you wrote a 
few messages ago was in error. Your error was your claim that free fall 
motion is like moving along a straight line in flat space. I suppose, 
loosely speaking I could agree. AG
 

*You know of course that in flat 3D Euclidean space a straight line is a 
geodesic. Don't you? *

*"No force is being applied to the space station but it is not following a 
Euclidean straight line because it is not in flat Euclidean space, it is in 
curved 4D non-Euclidean spacetime and is following a geodesic path. In 
curved 4D non-Euclidean spacetime the shortest path between any two points 
along the space station's orbit is the space station's orbit itself."*

*>> The sensitivity of the instrument is not the issue, no matter how 
sensitive it is if you pick a small enough region of space it will not be 
able to tell the difference, *


*> Indeed, it IS the issue. The enclosed observer must drop two test masses 
and determine any tendency for them to converge. So if the region is small 
enough, and the measurements sufficiently approximate, tidal forces, if 
they exist, won't be detected. AG *


*There is a limit on the precision that any real instrument can have 
because it will always produce an error, let's call it Ω, that is greater 
than zero. So no matter how small Ω is, I can always produce a finite 
region of space in which your instrument cannot detect a difference between 
gravitational mass and inertial mass. *


If a man is 6 ft tall, and you put him into an elevator of volume 1 cubic 
inch, will he be able to measure the convergence of two test particles he 
drops??? Sure, you can't always show the gravity and acceleration are 
equivalent, because they are not. AG
 

*And regardless of how large a volume of space you're interested in, 
provided it's not infinite, I can produce a large but finite sphere of 
matter that produces a gravitational field that your instrument cannot 
distinguish from acceleration. *

*And if in your thought experiment you want to conjure up an instrument 
that has infinite precision even though that would be unphysical then, if 
you're playing fair, you should allow me to conjure up a sphere made of 
matter that is of infinite size even though that is unphysical.*
 

*> This is Einstein's error;*


*When somebody on the Internet claims to have found an error that Einstein 
made that nobody had noticed before my built-in bullshit detector goes 
off.  It goes off a lot. My bullshit detector may not be perfect but it has 
served me pretty damn well over the years. *


I have no idea, nor do I care if anyone else has claimed that the EP is 
just an approximation, not truly a principle. AG 

 

*> mistaking an approximation for a principle. AG*


*The second law of thermodynamics is an approximation, but not only is it a 
superb approximation it is also the most important principle in physics. * 


It's not an approximation IMO, whereas the EP is. The latter appears to be 
true in some cases, and not in others, depening on the space allowed for 
the experiment and the accuracy of the measuring device. AG 


*> ** if an object which is falling toward the Sun is restrained by an 
external force and then let go, why does it move according to GR*


*The external force is provided to the object by your fingers, when you let 
go that external force suddenly stops and then just as suddenly the object 
starts following a geodesic path to the ground (not the sun) and then the 
force of the ground switches the object back to following a non-geodesic 
one which is the reason why it doesn't continue on to the center of the 
Earth. But during all of this you have continued to experience a force 
through the bottom of your feet. So you never stopped following a 
non-geodesic path and that's why the object is now on the ground and not 
still between your fingers.*

*> why is that path geodesic? AG*


*Both Newton and Einstein would give the same answer to that 
question. General Relativity and Newtonian Physics have one thing in 
common; they both say objects that are not experiencing a force always 
follow a path that is the shortest distance between two points, the only 
difference is in Newtonian physics were talking about flat 3-D Euclidean 
space (in which the geodesic is a Euclidean straight line with all the 
properties you were taught in high school) but in Einsteinian physics we're 
talking about curved 4D non-Euclidean spacetime where the geodesic is NOT a 
Euclidean straight line.*


Is that a postulate of GR? In GR, why does the test particle move when it 
is released from an external force while in a gravitational field, and take 
a geodesic path? You keep claiming the path is geodesic in GR, but can't 
say why. AG 


*>> I will say that if you're standing on the Earth's surface then you can 
NOT be in an initial state * 


*> For simplicity, imagine standing on a non-rotating Earth as the initial 
condition. AG*


*That won't help, you would still be following a non-geodesic path because 
a force is still being applied to the bottom of your feet. *


Sorry, but lately you seem a bit retarded. I know the path is non-geodesic 
in that case. Nowwhere did I deny that. I was answering your question of 
what "spatially at rest" means. I figured if the Earth is rotating, you 
could claim a person standing on the Earth would have his spatial 
coordinates change. AG
 

*That's why even if its rotation stopped you would still not fall to the 
center of the Earth. *

*John K Clark    See what's on my new list at  Extropolis 
<https://groups.google.com/g/extropolis>*

gaa 

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