On Thu, May 15, 2025 at 7:01 PM Brent Meeker <[email protected]> wrote:

*> My argument is with your statement that MWI means that all results
> consistent with Schroedinger's equation will occur, not with MWI.  Some
> results have zero probability, which means they don't occur.*
>

*I agree that Schrodinger's Wave Equation says the amplitude of the quantum
wave of a photon after it's gone through 2 polarizing filters set at
perpendicular angles is zero. Which means it has zero probability. Which
means it doesn't occur. I disagree that fact contradicts my statement that
all results consistent with Schroedinger's Equation will occur. According
to Many Worlds there is NO WORLD where the photon makes it through both
those filters, and there is NO WORLD where an electron decays into a proton
because both those things would violate Schrodinger's Wave Equation and the
fundamental laws of Quantum Mechanics.*

*John K Clark    See what's on my new list at  Extropolis
<https://groups.google.com/g/extropolis>*

8g3

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