On 5/14/2025 4:09 AM, John Clark wrote:
On Tue, May 13, 2025 at 3:36 PM Brent Meeker <[email protected]> wrote:


        *>> you are _assuming_ that only the electron must obey
        Schrodinger's Equation, _not_ the lab equipment needed to
        measure the electron, and most importantly _not_ the
        experimentalist who is looking at the measuring device; they
        still follow classical physics. That clumsy poorly defined
        assumption was just tacked on by the Copenhagen people because
        they were frightened by the logical consequence of not doing
        so. That's why Many Worlds is barebone no-nonsense Quantum
        Mechanics that contains everything that is necessary and not
        one bit more. As Richard Feynman said “nature isn't classical,
        dammit".*

    /> I made no such assumption.  You're just making up objections. 
    Are you asserting that a measurement does *not* leave a system in
    an eigenstate of the variable measured?/


*You are not the only Brent Meeker doing that exact same _measurement_! If Many Worlds is correct then there are an astronomical  number (or an infinite number) of yous in a world where the observable variable A has just been _measured_. In one of them _experimental results_ tell "you"  there is a 100% probability that "you" are in the world where the value of variable A is X is exactly equal to 1. But there are many many more Brent Meekers in which their _experimentation_ tells them that there is a 100% probability that variable A has a very different value than X. And all those Brent Meekers believe in Quantum Mechanics just as strongly as "you" do. *

    /> This has nothing to do with being observed or by whom/


*It most certainly does _IF_ the question asked is "what will an experimenter observe?" And that was the fundamental question Brent Meekerasked.
*

No, I referred to measurements and results, with no mention of observers.  You're thrashing straw men.  You're inserting the word "you".

And the correctness of MWI is what is in question, so you're begging the question by assuming it's true.  You seem to have missed the point of the argument which is based on successive measures of the same variable.  The second measurement has only one possible outcome contrary to you assertion that all values consistent with Schroedinger's equation must obtain; thereby neglecting the role of state preparation.

Brent

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