Viesturs, I was testing in Aluminum, but I think that for a given spindle HP your results would be similar in other materials. If you're on an open loop machine it's preferable to size the motors such that you stall the spindle before stalling an axis motor because it's often an easier failure mode to detect.
If you're only using small end mills, then the max axis force required is simply just a bit more than the force required to snap the end mill. I would think that a 6mm end mill wouldn't be capable of delivering 1.5 HP to a workpiece. It's nice (and somewhat surprising) that the website you referenced comes up with nearly the same numbers as my recollection of results from a couple years ago. Formulas like the one listed on that site usually seem to only be good within an order of magnitude. Rogge -----Original Message----- From: Viesturs Lācis [mailto:[email protected]] Sent: Monday, July 02, 2012 1:23 PM To: Enhanced Machine Controller (EMC) Subject: Re: [Emc-users] Plasma 2012/7/2 Daniel Rogge <[email protected]>: > > It depends what kind of machining you'll be doing - the forces in milling are > lower than those in drilling. Based on some axis motor testing I did a > couple years back, I would guess at a conservative estimate of around 250 lbs > per spindle horse power for the worst-case machining parameters. For > example, if you have a 2hp spindle and you're using all 2hp, you'll need to > deliver 500 lbs of thrust along the axis of cut. > Thank You! Just a small question - what material do these numbers refer to? I am interested in aluminium. I was thinking about Kress 1050 motor, which has 1kW power, which is 1,5 hp, so based on these figures I am looking at 375 lbs = 170 kg of load. That is a lot. I found this one: http://www.carrlane.com/Catalog/index.cfm/29625071F0B221118070C1C513906103E0B05543B0B012009083C3B2853514059482013180B041D1E173C3B2853524B5A59 Figure 3-10 gives a formula. The starting data I used are: Tool diameter = 6 mm Spindle speed = 5000 RPM (smallest number the Kress 1050 will do) Spindle power = 1,5 hp So max cutting force with given spindle and tool diameter in any material would be 54,5 kg. Much better than 170 kg. Viesturs If you can't fix it, you don't own it. http://www.ifixit.com/Manifesto ------------------------------------------------------------------------------ Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ _______________________________________________ Emc-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/emc-users ------------------------------------------------------------------------------ Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ _______________________________________________ Emc-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/emc-users
