Good Evening,
The bands were noisier than I had expected. The was mild QSB on
twenty meters with a little higher level on forty.
On 14050.5 kHz at 2200z:
W0CZ - Ken - ND
K6XK - Roy - IA
K4JPN - Steve - GA
K6PJV - Dale - CA
K0DTJ - Brian - CA
W8OV - Dave - TX
On 7047.8 kHz at 0000z:
WM5F - Dwight - ID
K0DTJ - Brian - CA
K6PJV - Dale - CA
Until next week 73,
Kevin. KD5ONS
-
I wanted to see how strongly the solar wind affects the Earth's
magnetosphere. I scanned the web and found some consensus numbers.
There are approximately 10 electrons per cubic centimeter in the wind,
on average. The wind varies from 250 to 750 kilometers per second.
Electron density and a flow rate is enough information to determine current.
The theory talks about flow through a surface. So each spherical sample
can be reduced to the wind's rate through the circular area. I chose
the midpoint of the wind speed to make the numbers easier to
manipulate. That gave me:
10 electrons/cc * 500 km/s * 10,000 cm/km = 50*10^6 electrons/s per
square centimeter
One Coulomb = 1/1.6*10^-19 electrons = 6.25*10^18 electrons
50*10^6 e/s / 6.25*10^18 electrons/Coulomb = 8*10^-12 Coulomb/second =
8 pico Ampere
If I did this correctly every square centimeter, hit by the solar wind,
experiences 8 pA of current. Now, do I integrate over the entire
sunward side of the magnetosphere to get the total current? I am more
interested in the local effects on the magnetic field lines.
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