> However when I get the query from
> request.POST, it throws up server error (500).
Well, I kind of doubt that jQuery in the browser is causing a 500
error on the server.
I strongly recommend setting DEBUG=True in your settings.py file.
Django gives you a perfectly lovely, formatted stack trace, complete
with source code windows and local variables.
> > if request.POST.has_key('query'):
> query = unicode(request.POST['query'])
> qfld = unicode(request.POST['qtype'])
> if (query):
> qfilter= {"%s__contains" % qfld : query}
> books = Book.objects.filter(**qfilter)
The first guess I would make is that one of the if conditions
evaluates to False and then later code (maybe in the context being
passed to the template) is referencing a variable that was never set.
> (From front end, I am passing the same values - cep and publisher)
My gut says this may not be a correct statement. Once you have DEBUG
turned on you may immediately see the error of your ways. If not,
trying putting a statement of 1/0 just before the first if. This will
cause a Divide by Zero error, and give you that stack trace *and* all
of the environment values that Django has.
HTH,
Peter
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