On Thu, Nov 01, 2007 at 04:06:39AM +0100, Christoph Mallon wrote:
> Andrey Chernov wrote:
>> On Thu, Nov 01, 2007 at 02:44:25AM +0100, Christoph Mallon wrote:
>>> Also the example is still unrealistic: You usually don't multiply chars
>>> by two. Lets try something more realistic: an ASCII filter
>>>
>>> int filter_ascii0(int c)
>>> {
>>> return c < 0 || c >= 128 ? '?' : c;
>>> }
>>>
>>> int filter_ascii1(int c)
>>> {
>>> return c & ~0x7F ? '?' : c;
>>> }
>> We don't need that reaslistic examples, we need only what __isctype()
>> does, and it just returns 0 or 1, not 'c'.
>
> Sorry, I don't understand what you want to tell me. I showed, that your
> example is invalid (because of undefined behaviour) and unrealistic,
> therefore I provided a better example on how this condition is used. But,
> of course, let's look at __isctype() in both variants:
Just backed out.
--
http://ache.pp.ru/
_______________________________________________
cvs-all@freebsd.org mailing list
http://lists.freebsd.org/mailman/listinfo/cvs-all
To unsubscribe, send any mail to "[EMAIL PROTECTED]"
