On Seq, no, but you can use a transducer to make it read-ahead.

Eg :
https://gist.github.com/cgrand/c8fa256c9ed8331f9cf1

from Christophe Grand.

On Oct 18, 2014 8:18 PM, "shahrdad shadab" <clojure.langu...@gmail.com>
wrote:

> Thanks a lot for your explanation, the thing that confuses me was the same
> function used with "repeatedly" only prints once:
>
> (first (repeatedly 4 #(do (println "executed!") (inc 1))))
>
> I guess because Clojure does not read-ahead in this scenario. Am I right?
>
> On Sat, Oct 18, 2014 at 1:41 PM, Jonathan Winandy <
> jonathan.wina...@gmail.com> wrote:
>
>> You can try in you repl with
>>
>> (take 1 (map (fn [_]  (println "executed")) (vec (range 100))))
>> (take 32 (map (fn [_]  (println "executed")) (vec (range 100))))
>> (take 33 (map (fn [_]  (println "executed")) (vec (range 100))))
>>
>>
>> you will observe the 32 sized chunks.
>>
>>
>>
>> On Sat, Oct 18, 2014 at 7:36 PM, James Reeves <ja...@booleanknot.com>
>> wrote:
>>
>>> Some lazy lists are chunked for efficiency, which means Clojure will
>>> read-ahead and evaluate a number of elements in advance. Often the outputs
>>> from the various list handling functions are chunked (e.g. map, range,
>>> etc.), while creating a seq explicitly with lazy-seq will not be chunked.
>>>
>>> - James
>>>
>>> On 18 October 2014 18:28, shahrdad shadab <clojure.langu...@gmail.com>
>>> wrote:
>>>
>>>> Greeting everyone,
>>>>
>>>>  It might be stupid question but I expect
>>>>
>>>>  (first (map (fn [_]  (println "executed")) [1 2 3 4]))
>>>>
>>>> prints only once (realizing only first element in lazy seq returned by
>>>> map) but it prints four times.
>>>>  Can some one shed a light why?
>>>>
>>>> Thanks in advance
>>>> Best regards
>>>> Shahrdda
>>>>
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