Snippet you showed before is also not an atomic. If you want strictly to 
avoid recomputations you need something more elaborate.
May be this

(def cache (atom {}))
 
(defn unwrap [v]
  (if-let [a (get v ::atom)]
    @a
    v))
 
(defn compute [cache k]
  (let [p {::atom (atom nil)}
        c (swap! cache assoc k p)
        val (get c k)]
    (when (identical? val p)
      (swap! (::atom p) (fn [_] (calc-value k)))
      (swap! cache assoc k @(::atom p)))
    (unwrap val)))
 
(defn lookup [cache k]
  (let [v (get @cache k ::nil)]
    (if (= v ::nil)
      (compute cache k)
      (unwrap v))))

  

суббота, 30 августа 2014 г., 11:18:51 UTC+4 пользователь Colin Fleming 
написал:
>
> True, but only if you don't mind possibly calculating the value more than 
> once since the update is not atomic.
>
>
> On 30 August 2014 18:31, Eldar Gabdullin <elda...@gmail.com <javascript:>> 
> wrote:
>
>> Something like the following would be fine for me
>>
>> (def cache (atom {}))
>>  
>> (defn lookup [cache k]
>>
>>   (let [v (get @cache k ::nil)]
>>
>>     (if (= v ::nil)
>>
>>       (let [v (calc-value k)]
>>
>>         (swap! cache assoc k v)
>>
>>         v)
>>       v)))
>>  
>> (let [value (lookup cache k)]
>>
>>   ; use value and @cache here
>>   )
>>
>>
>> суббота, 30 августа 2014 г., 9:27:05 UTC+4 пользователь Colin Fleming 
>> написал:
>>
>>> Hi all,
>>>
>>> I want to use a map to cache values based on a key. I'm planning to use 
>>> an atom for this. My basic operation is "give me the value for this key" - 
>>> if the value exists in the map then that value should be returned, 
>>> otherwise a new value should be calculated, inserted in the map and then 
>>> returned. My plan is to implement something like the following:
>>>
>>>
>>> (defn ensure [cache key]  (if (contains? cache key)    cache    (assoc 
>>> cache key (calc-value key))))(let [value (get (swap! cache ensure key) 
>>> key)]  ... do my thing with value ...)
>>>
>>>
>>> So 'ensure' ensures that the cache contains the value for key, the swap! 
>>> operation returns the cache with the value and then I get it out. This 
>>> works but feels a little clumsy, is there a better way to do this?
>>>
>>> Also, looking at the Atom source code, I see that this will cause a CAS 
>>> operation even if the value returned from swap! is identical to the 
>>> original value. It seems like a reasonable optimisation would be to check 
>>> if the values are identical and not update if so - is there a reason this 
>>> might not be a good idea?
>>>
>>> Thanks,
>>> Colin
>>>
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