If sets don't have a set ordering, then why should seq on a set always
return the same order for the same set?

If seq doesn't always return the a seq with the same order, then (nth
set 5) might be different than a future call to (nth set 5),
because the underlying sequence returned by the set might change.

If seq on a set always returns a seq with the same order, then that
may limit the future efficiency of sets.

--Robert McIntyre


On Sun, Dec 5, 2010 at 8:08 PM, Sunil S Nandihalli
<sunil.nandiha...@gmail.com> wrote:
> +1 to what Ken said
> Sunil
>
> On Mon, Dec 6, 2010 at 4:04 AM, Ken Wesson <kwess...@gmail.com> wrote:
>>
>> On Sun, Dec 5, 2010 at 4:14 PM, jweiss <jeffrey.m.we...@gmail.com> wrote:
>> > That's totally different than nth for a set being undefined.  It's
>> > undefined
>> > on purpose.
>> >
>> > Now, if you are using a sorted-set, then you have a point there, I
>> > would expect that nth means something then.  But yeah, clojure doesn't
>> > let you call nth on it directly, you have to make a seq out of it
>> > first.
>>
>> I vote to make nth work on sets and maps, in general, sorted and
>> otherwise, with the well-defined semantics of (identical? (nth
>> set-or-map) (nth (seq (set-or-map)))). More generally, let nth work on
>> anything that seq works on, by calling seq on its argument when
>> necessary.
>>
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