On Mon, 4 May 2009 06:16:14 -0700 (PDT)
Drew Raines <aarai...@gmail.com> wrote:
>
> On May 4, 8:05 am, Drew Raines <aarai...@gmail.com> wrote:
>
> > user> (let [test-str "foo=1;bar=2;baz=3"]
> > (reduce conj {}
> > (map #(apply hash-map (seq (.split % "=")))
> > (.split test-str ";"))))
>
> Whoops, that (seq) is a debugging artifact. You can remove that:
>
> (let [test-str "foo=1;bar=2;baz=3"]
> (reduce conj {}
> (map #(apply hash-map (.split % "="))
> (.split test-str ";"))))
Ok, my example seems to have misled. You're missing the point a little
bit:
1. I was trying to avoid the (reduce conj {} ...), by having the map
function do it. Why even build a list that's only going to get thrown
away when I want a hash-map at the end?
2. The functions used to split the strings were not important, only an
example. It could just as easily be a function to extract fields from a
java object.
To some extent, I guess I'm thinking in terms of Common Lisp, where I'd
build an a-list with mapcar and cons.
Nathan
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