> On Jun 21, 2021, at 5:23 AM, ben via cctalk <cctalk@classiccmp.org> wrote: > > ... > I want to transformatiom before full parsing expressions, as a text process. > string "a+(b+c)*c" becomes "((b+c)*c)a+". As an academic exercise that's pretty trivial. But why would you want to do that? Apparently some people think that this is how you create expression parsers, but that isn't actually a useful or necessary approach. It's entirely trivial to do a sequential scan over the expression tokens and produce corresponding code, in one pass without backtracking or text manipulation. BTW, on code generation: it's true that this is complex, and a still evolving field, if you consider optimization. But a straightforward code generator fed by the parse tree isn't very hard, and requires no great magic. I still have the one I wrote in compiler class back in 1976; it took a week of work and that included learning Pascal and linked lists. paul
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