Because you don't have direct spoke-to-spoke communication (e.g. no DLCI's 
between your spokes). This means EVERYTHING must travel up to the hub first. 
It's the same thing with your frame maps where you map everything to the DLCI 
on the hub in order to ping the spokes. Makes sense?

-----Original Message-----
From: [email protected] 
[mailto:[email protected]] On Behalf Of Bill Riley
Sent: Wednesday, October 12, 2011 5:41 AM
To: 'Adam Booth'
Cc: [email protected]
Subject: Re: [OSL | CCIE_RS] IPExpert Vol1 6.9

Yes they are on the same subnet.  When I do a trace route it does go to the
HUB first and then to the spoke so it is not direct. Still trying to
understand why it does that. Is it just inherent in the PPPoFR
configuration?

 

 

From: Adam Booth [mailto:[email protected]] 
Sent: Tuesday, October 11, 2011 5:22 PM
To: Bill Riley
Cc: [email protected]
Subject: Re: [OSL | CCIE_RS] IPExpert Vol1 6.9

 

Hi Bill,

I will assuming that on your routers the virtual-templates exist on the same
subnet.

If you do a show ip route on each of the routers you will see a connected
route for the network the virtual-template is associated with and a /32
route for the direct peer through the virtual-access interface

Connectivity between spokes occurs via the hub and requires routing and
relies on longest match rules and the ppp peer neighbor routes.

For spoke to spoke, the spoke will send traffic to the hub, which then will
have an exact match for the other spoke due to the ppp neighbor route and be
able to select the appropriate virtual-access to reach the other spoke.

If you perform a traceroute between spokes even though these are on the same
subnet, you will see the hub as a hop to reach the other spoke.

Cheers,
Adam



On Wed, Oct 12, 2011 at 5:39 AM, Bill Riley <[email protected]>
wrote:



Why is it when I configure the DLCI's using PPP I get a fully meshed network
and can ping all the spoke sites even though the local DLCI is only setup to
reach the hub site of R2?





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