>> I need to convert a number like this:   -3205.0569059
>> ... into an 8-byte double (big and little endian), e.g. 4f 3e 52 00 2a
> bc 93
>> d3  (I just made up those 8 byte values).
>> 
>> Is this easy in perl?  Are long and short ints easy as well?
> 
> The sprintf() family is your friend.


I see %x (unsigned integer, in hexadecimal) and %f (floating-point number,
in fixed decimal notation), but nothing about doubles, endianness, etc.

I checked both my perl bookshelf and perldoc on this so far with no luck...

- Bryan



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