From: Uri Guttman >>>>>> "BM" == Bob McConnell <r...@cbord.com> writes: > > BM> From: Bryan R Harris > >> > >> I need to convert a number like this: -3205.0569059 > >> ... into an 8-byte double (big and little endian), e.g. 4f 3e 52 00 2a > BM> bc 93 > >> d3 (I just made up those 8 byte values). > >> > >> Is this easy in perl? Are long and short ints easy as well? > > BM> The sprintf() family is your friend. > > that will only generate text (hex and other formats). he needs pack > which does exactly what he wants. read perlpacktut for a tutorial on > pack/unpack and then perlfunc -f pack for the reference on it.
That statement just confuses me. His initial value of -3205.0569059 is also text. It is the human readable representation of the number, and is not anything like what it looks like inside the computer. He just asked for a different format for that text. Why is sprintf not a reasonable way to do that? Bob McConnell -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
