Tony I’m sure you are right but I just don’t get it
The BCTG instruction is at location 2E60 LONGDISP is at location A0 so the displacement is 2E60 - A0 = 2DC0 Thanks On Wed, Feb 26, 2025 at 8:27 AM Tony Thigpen <t...@vse2pdf.com> wrote: > LONGDISP is actually only x'A0' from R9, it's base, so the branch is > generated correctly as R9+x'A0'. > > Tony Thigpen > > Joe Reichman wrote on 2/26/25 7:51 AM: > > Hi > > > > > > My understanding of this new instruction is that it is a BCT with a new > 20 > > bit displacement. > > > > The object code layout of this6 byte instruction has in bit 20 - 31 the > 12 > > bit displacement and if the address exceeds 4096 decimal the new bit > > displacement would get populated in bits > > > > 32 - 40 > > > > I tried out a BCTG R9,LONGDISP > > > > Where the address of longdisp was beyond 4096 and yet I don't see bits > 32 - > > 40 of the instruction being populated > > > > So here is the example > > > > LONGDISP is beyond 4,096 and in bits 31 - 40 there is zeros > > > > > > 00A0 LONGDISP DS 0H > > > > 2E60 E390 00A0 00 46 BCTG > R9,LONGDISP > > >
