Hi
My understanding of this new instruction is that it is a BCT with a new 20 bit displacement. The object code layout of this6 byte instruction has in bit 20 - 31 the 12 bit displacement and if the address exceeds 4096 decimal the new bit displacement would get populated in bits 32 - 40 I tried out a BCTG R9,LONGDISP Where the address of longdisp was beyond 4096 and yet I don't see bits 32 - 40 of the instruction being populated So here is the example LONGDISP is beyond 4,096 and in bits 31 - 40 there is zeros 00A0 LONGDISP DS 0H 2E60 E390 00A0 00 46 BCTG R9,LONGDISP
