@Sukun: these probabilities should have been given in the questn.. since
it's not given and there are 3 possible answers, i considered probability
of each one of them to b correct as 1/3 (since there are 3 possible answers
and only one answer is correct)

On Sun, Sep 9, 2012 at 12:48 AM, Sukun Tarachandani <[email protected]>wrote:

> How do you get P(0.25 being correct) = P(0.5 being correct) = P(0.6 being
> correct) = 1/3?
>
>
> On Saturday, September 8, 2012 4:42:51 PM UTC+5:30, Shruti wrote:
>
>> shouldn't it b done like this :
>>
>> P(correct answer when choosing randomly )= P(choosing 0.25)*P(0.25 being
>> correct ans)+ P(choosing 0.60)*P(0.60 being correct ans) + P(choosing
>> 0.50)*P(0.50 being correct ans)
>>
>>
>> = 2/4*1/3  +  1/4*1/3  +  1/4*1/3     [since 3 possible answers, hence
>> prob of an ans being correct=1/3]
>>
>> taking 1/3 common,
>> =1/3(2/4+1/4+1/4)
>> =1/3
>>
>> pls correct me if i'm wrong
>>
>> On Fri, Sep 7, 2012 at 7:54 PM, isandeep <[email protected]> wrote:
>>
>>> Ans : 0.5
>>>
>>> there is two cases :
>>>
>>> i) if correct ans is 0.25
>>>     probability will be 2/4 = 0.5
>>> ii) if correct ans is 0.6 or 0.50
>>>     probability will be 1/3 = 0.33
>>>
>>> since 0.33 is not in option so correct answer will be 0.5.
>>>
>>> On Friday, September 7, 2012 6:05:08 PM UTC+5:30, noname wrote:
>>>>
>>>> [image: -]14Answers <http://www.careercup.com/question?id=14553727>
>>>>
>>>> What is the probability of being the answer correct for this question,
>>>> when the answer is chosen randomly:
>>>>
>>>> a. 0.25
>>>> b. 0.60
>>>> c. 0.25
>>>> d. 0.50
>>>>
>>>>
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