How do you get P(0.25 being correct) = P(0.5 being correct) = P(0.6 being correct) = 1/3?
On Saturday, September 8, 2012 4:42:51 PM UTC+5:30, Shruti wrote: > > shouldn't it b done like this : > > P(correct answer when choosing randomly )= P(choosing 0.25)*P(0.25 being > correct ans)+ P(choosing 0.60)*P(0.60 being correct ans) + P(choosing > 0.50)*P(0.50 being correct ans) > > > = 2/4*1/3 + 1/4*1/3 + 1/4*1/3 [since 3 possible answers, hence > prob of an ans being correct=1/3] > > taking 1/3 common, > =1/3(2/4+1/4+1/4) > =1/3 > > pls correct me if i'm wrong > > On Fri, Sep 7, 2012 at 7:54 PM, isandeep <[email protected] <javascript:> > > wrote: > >> Ans : 0.5 >> >> there is two cases : >> >> i) if correct ans is 0.25 >> probability will be 2/4 = 0.5 >> ii) if correct ans is 0.6 or 0.50 >> probability will be 1/3 = 0.33 >> >> since 0.33 is not in option so correct answer will be 0.5. >> >> On Friday, September 7, 2012 6:05:08 PM UTC+5:30, noname wrote: >>> >>> [image: -]14Answers <http://www.careercup.com/question?id=14553727> >>> >>> What is the probability of being the answer correct for this question, >>> when the answer is chosen randomly: >>> >>> a. 0.25 >>> b. 0.60 >>> c. 0.25 >>> d. 0.50 >>> >>> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To view this discussion on the web visit >> https://groups.google.com/d/msg/algogeeks/-/SE8PpC7PLwgJ. >> >> To post to this group, send email to [email protected]<javascript:> >> . >> To unsubscribe from this group, send email to >> [email protected] <javascript:>. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/z2HuFFlPSWYJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
