shouldn't it b done like this : P(correct answer when choosing randomly )= P(choosing 0.25)*P(0.25 being correct ans)+ P(choosing 0.60)*P(0.60 being correct ans) + P(choosing 0.50)*P(0.50 being correct ans)
= 2/4*1/3 + 1/4*1/3 + 1/4*1/3 [since 3 possible answers, hence prob of an ans being correct=1/3] taking 1/3 common, =1/3(2/4+1/4+1/4) =1/3 pls correct me if i'm wrong On Fri, Sep 7, 2012 at 7:54 PM, isandeep <[email protected]> wrote: > Ans : 0.5 > > there is two cases : > > i) if correct ans is 0.25 > probability will be 2/4 = 0.5 > ii) if correct ans is 0.6 or 0.50 > probability will be 1/3 = 0.33 > > since 0.33 is not in option so correct answer will be 0.5. > > On Friday, September 7, 2012 6:05:08 PM UTC+5:30, noname wrote: >> >> [image: -]14Answers <http://www.careercup.com/question?id=14553727> >> >> What is the probability of being the answer correct for this question, >> when the answer is chosen randomly: >> >> a. 0.25 >> b. 0.60 >> c. 0.25 >> d. 0.50 >> >> > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/algogeeks/-/SE8PpC7PLwgJ. > > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
