I guess 720 must be the ans. Its like forming three-letter words out of given 6 without repetition. In that case = 6p3 * 3!
On Thu, Sep 6, 2012 at 3:53 PM, atul anand <[email protected]> wrote: > seems output should be 20. > > > On Thu, Sep 6, 2012 at 3:26 PM, tendua <[email protected]> wrote: > >> from the set {a,b,c,d,e,f} find number of arrangements for 3 alphabets >> with no data repeated? >> Answer given is 360. but how? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To view this discussion on the web visit >> https://groups.google.com/d/msg/algogeeks/-/E4U2XlfkvgMJ. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- best wishes!! Vaibhav -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
