Can you send the link to the question.

On Thu, Sep 6, 2012 at 4:35 PM, tendua <[email protected]> wrote:

> from the six elements, we could choose any three in C(6,3) ways which is
> 20 and then permute all the three elements so it will be multiplied by 3!
> which is 6. Hence, 20*6 = 120. We still have to multiply it by 3 to get 360
> but I'm not getting why?
>
>
> On Thursday, September 6, 2012 3:54:11 PM UTC+5:30, atul007 wrote:
>
>> seems output should be 20.
>>
>> On Thu, Sep 6, 2012 at 3:26 PM, tendua <[email protected]> wrote:
>>
>>> from the set {a,b,c,d,e,f} find number of arrangements for 3 alphabets
>>> with no data repeated?
>>> Answer given is 360. but how?
>>>
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