from the six elements, we could choose any three in C(6,3) ways which is 20 and then permute all the three elements so it will be multiplied by 3! which is 6. Hence, 20*6 = 120. We still have to multiply it by 3 to get 360 but I'm not getting why?
On Thursday, September 6, 2012 3:54:11 PM UTC+5:30, atul007 wrote: > > seems output should be 20. > > On Thu, Sep 6, 2012 at 3:26 PM, tendua <[email protected] > <javascript:>>wrote: > >> from the set {a,b,c,d,e,f} find number of arrangements for 3 alphabets >> with no data repeated? >> Answer given is 360. but how? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To view this discussion on the web visit >> https://groups.google.com/d/msg/algogeeks/-/E4U2XlfkvgMJ. >> To post to this group, send email to [email protected]<javascript:> >> . >> To unsubscribe from this group, send email to >> [email protected] <javascript:>. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/VMO1othQRcQJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
