--- On Mon, 9/24/12, Richard Elling <richard.ell...@gmail.com> wrote:
I'm hoping the answer is yes - I've been looking but do not see it ...
none can hide from dtrace!# dtrace -qn 'dsl_dataset_stats:entry {this->ds =
(dsl_dataset_t *)arg0;printf("%s\tcompressed size = %d\tuncompressed
size=%d\n", this->ds->ds_dir->dd_myname,
this->ds->ds_phys->ds_compressed_bytes,
this->ds->ds_phys->ds_uncompressed_bytes)}'openindiana-1 compressed size =
3667988992 uncompressed size=3759321088
[zfs get all rpool/openindiana-1 in another shell]
For reporting, the number is rounded to 2 decimal places.
Ok. So the dedupratio I see for the entire pool is
"dedupe ratio for filesystems in this pool that have dedupe
enabled" ... yes ?
Thank you - appreciated.
Doesn't that mean that if I enabled dedupe on more than one filesystem, I can
never know how much total, raw space each of those is using ? Because if the
dedupe ratio is calculated across all of them, it's not the actual ratio for
any one of them ... so even if I do the math, I can't decide what the total raw
usage for one of them is ... right ?
Correct. This is by design so that blocks shared amongst different datasets
canbe deduped -- the common case for things like virtual machine images.
Ok, but what about accounting ? If you have multiple deduped filesystems in a
pool, you can *never know* how much space any single one of them is using ?
That seems unbelievable...
Ok - but from a performance point of view, I am only using
ram/cpu resources for the deduping of just the individual
filesystems I enabled dedupe on, right ? I hope that
turning on dedupe for just one filesystem did not incur
ram/cpu costs across the entire pool...
It depends. -- richard
Can you elaborate at all ? Dedupe can have fairly profound performance
implications, and I'd like to know if I am paying a huge price just to get a
dedupe on one little filesystem ...
Thanks again.
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