ERRATA^3
I like to define
def HiddenField(*a,**b):
b['writable']=b['readable']=False
return Field(*a,**b)
and use
db.define_table('mytable',Field('name'),HiddenField('manager'))
On Sep 17, 11:53 am, Fabio Alessandro Locati <[email protected]> wrote:
> thank you guys, it works perfectly :)
>
> 2010/9/17 Jonathan Lundell <[email protected]>
>
> > On Sep 17, 2010, at 6:25 AM, mdipierro wrote:
>
> > > ERRATA:
>
> > > I like to define
>
> > > def HiddenField(*a,**b):
> > > a['writable']=b['readable']=False
> > > return Field(*a,**b)
>
> > I *think* you mean:
>
> > b['writable']=b['readable']=False
>
> > > and use
>
> > > db.defiend_table('mytable',Field('name'),HiddenField('manager'))
>
> > and db.define_table(...
>
> > > On Sep 17, 8:22 am, mdipierro <[email protected]> wrote:
> > >> I like to define
>
> > >> def HiddenField(*a,**b):
> > >> a['writable']=b['readable']=False
>
> > >> and use
>
> > >> db.defiend_table('mytable',Field('name'),HiddenField('manager'))
>
> > >> On Sep 17, 6:07 am, "Martin.Mulone" <[email protected]> wrote:
>
> > >>> To hide a field:
> > >>> Field('out','boolean',writable=False,readable=False)
>
> > >>> And computed fields in book:
> >http://web2py.com/book/default/chapter/06#Computed-Fields
>
> > >>> On 17 sep, 05:58, Fabio Alessandro Locati <[email protected]> wrote:
>
> > >>>> Hi,
> > >>>> I'm trying to make a form with a hidden field, but I haven't found the
> > way
> > >>>> to do it :(.
>
> > >>>> I have a table:
> > >>>> db.define_table('partners',
> > >>>> Field('name','string'),
> > >>>> Field('out','boolean'))
>
> > >>>> I want to ask to the user the name of the partner and, based on the
> > name of
> > >>>> the page, the value of 'out'. I was thinking into making two different
> > pages
> > >>>> one that has - at code level - out=1 and the other one that had out=0.
> > How
> > >>>> can I do this, without showing to the user the existence of the 'out'
> > field?
>
> > >>>> Thanks :)
>
>
