ERRATA:
I like to define
def HiddenField(*a,**b):
a['writable']=b['readable']=False
return Field(*a,**b)
and use
db.defiend_table('mytable',Field('name'),HiddenField('manager'))
On Sep 17, 8:22 am, mdipierro <mdipie...@cs.depaul.edu> wrote:
> I like to define
>
> def HiddenField(*a,**b):
> a['writable']=b['readable']=False
>
> and use
>
> db.defiend_table('mytable',Field('name'),HiddenField('manager'))
>
> On Sep 17, 6:07 am, "Martin.Mulone" <mulone.mar...@gmail.com> wrote:
>
> > To hide a field:
> > Field('out','boolean',writable=False,readable=False)
>
> > And computed fields in
> > book:http://web2py.com/book/default/chapter/06#Computed-Fields
>
> > On 17 sep, 05:58, Fabio Alessandro Locati <floc...@grimp.eu> wrote:
>
> > > Hi,
> > > I'm trying to make a form with a hidden field, but I haven't found the way
> > > to do it :(.
>
> > > I have a table:
> > > db.define_table('partners',
> > > Field('name','string'),
> > > Field('out','boolean'))
>
> > > I want to ask to the user the name of the partner and, based on the name
> > > of
> > > the page, the value of 'out'. I was thinking into making two different
> > > pages
> > > one that has - at code level - out=1 and the other one that had out=0. How
> > > can I do this, without showing to the user the existence of the 'out'
> > > field?
>
> > > Thanks :)
>
>
