Wow, thanks very much for sharing this trick. I knew it could be easy
and elegant! :-)
On Jun20, 10:15pm, mdipierro <mdipie...@cs.depaul.edu> wrote:
> Because the form is submitted and returned via ajax the usual
> mechanism does not work but you can do:
>
> def form():
> form=SQLFORM.factory(
> Field('name', requires=IS_NOT_EMPTY()))
> if form.accepts(request.vars, session):
> response.headers['web2py-component-flash'] = 'form accepted'
> else:
> response.headers['web2py-component-flash'] = 'form has errors'
> return form
>
> I.E. place the flash in a HTTP header and web2py will read it and
> place it in the flash box.
>
> On Jun 19, 11:23 am, Julius Minka <j...@minka.sk> wrote:
>
>
>
> > def form():
> > form=SQLFORM.factory(
> > Field('name', requires=IS_NOT_EMPTY()))
> > if form.accepts(request.vars, session):
> > response.flash = 'form accepted'
> > else:
> > response.flash = 'form has errors'
> > return form
>
> > Flash is not displayed in this place, elsewhere is working. Why?
> > Or, how let user know about the result of form submission?
>
> > V Sobota, 19. jún 2010 o 00:41 -0700, mdipierro napísal(a):
>
> > > Just do
>
> > > def contact():
> > > form=SQLFORM.factory(....)
> > > if form.accepts(....)
> > > return form # not dict(form=form)
>
> > > and in layout.html
>
> > > {{=LOAD('default','contact')}}
>
> > > On Jun 18, 11:26 am, Julius Minka <j...@minka.sk> wrote:
> > > > I need a contact form (name, address,...) on every page of a web site.
> > > > Thinking about putting the form into layout.html and use some Ajax to
> > > > send entered values to be processed by a controller. I would like to
> > > > avoid page reload on form submission.
>
> > > > I found 2 possible solutions in the archive:
> > > > 1.http://groups.google.com/group/web2py/browse_thread/thread/f162f35e4a...
> > > > Is this incomplete? How process function is called?
>
> > > > 2.http://groups.google.com/group/web2py/browse_thread/thread/82fad17e26...
> > > > I ran application mentioned in the thread. This is probably close, but
> > > > complicated.
>
> > > > What is good and simple approach to this issue? I do not have much
> > > > experience with Ajax.
>
> > > > Thanks
> > > > Julius
