Sorry I did not see your answer Mdipierro.
I did not try using custom HTML with beginning with {{=form.custom.begin}},
I just started as mentionned in the online book
http://web2py.com/book/default/section/7/2 SQL form in HTML.
JmiXIII
2010/4/23 mdipierro <mdipie...@cs.depaul.edu>
> You can. Did you try
>
> {{=form.custom.begin}}
> <input ....>
> {{=form.custom.end}}
>
> On Apr 22, 11:35 pm, Paul Wray <paul.w...@det.nsw.edu.au> wrote:
> > I too have tried this without success.
> >
> > I seems that you cannot use a custom form together with SQLFORM with
> > record=
> > Is that true?
> >
> > Paul
> >
> > On Apr 9, 6:14 am, JmiXIII <sylvn.p...@gmail.com> wrote:
> >
> > > Hello,
> >
> > > I'm using a SQLFORM with a html custom (as described in book/7.2 =>
> > > SQLFORM in HTML)
> > > My fonction inside my controller is :
> >
> > > def ncmodif():
> > > ### Formulaire de saisie des NC de production
> > > rec=db(db.NC.id==269).select()[0]
> > > form=SQLFORM(db.NC,record=rec)
> > > if form.accepts(request.vars,formname='test'):
> > > response.flash = 'form accepted'
> > > elif form.errors:
> > > response.flash = 'form has errors'
> > > else:
> > > response.flash = 'please fill the form'
> > > return dict()
> >
> > > I have hardcoded db.NC.if==269 for the moment to see how it works.
> >
> > > My view is something like:
> > > <form><input name="FieldName"/>....<input type="hidden"
> > > name="_formname" value="test" />....
> >
> > > My question is there a simple way to make this form work as it works
> > > with the standard way (ie when using {{=form}}) to update the record
> > > via the custom form ?
> > > Can I have the input field prepopulated and updated when I submit
> > > since ncmodif() does not return any value ?
> >
> > > Thanks
> >
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