I too have tried this without success.
I seems that you cannot use a custom form together with SQLFORM with
record=
Is that true?
Paul
On Apr 9, 6:14 am, JmiXIII <sylvn.p...@gmail.com> wrote:
> Hello,
>
> I'm using a SQLFORM with a html custom (as described in book/7.2 =>
> SQLFORM in HTML)
> My fonction inside my controller is :
>
> def ncmodif():
> ### Formulaire de saisie des NC de production
> rec=db(db.NC.id==269).select()[0]
> form=SQLFORM(db.NC,record=rec)
> if form.accepts(request.vars,formname='test'):
> response.flash = 'form accepted'
> elif form.errors:
> response.flash = 'form has errors'
> else:
> response.flash = 'please fill the form'
> return dict()
>
> I have hardcoded db.NC.if==269 for the moment to see how it works.
>
> My view is something like:
> <form><input name="FieldName"/>....<input type="hidden"
> name="_formname" value="test" />....
>
> My question is there a simple way to make this form work as it works
> with the standard way (ie when using {{=form}}) to update the record
> via the custom form ?
> Can I have the input field prepopulated and updated when I submit
> since ncmodif() does not return any value ?
>
> Thanks
>
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