Try db.videodata.insert(flvcopy=db.videodata.flvcopy.store (request.vars.Filedata.file,'test1.flv'))
On Oct 21, 2:13 am, Adi <aditya.sa...@gmail.com> wrote: > Here's an update: > > The POST request when seen as text looks like this: > > ------------cH2Ij5cH2ae0gL6Ef1ae0cH2KM7ae0 > Content-Disposition: form-data; name="Filename" > > test video.flv > ------------cH2Ij5cH2ae0gL6Ef1ae0cH2KM7ae0 > Content-Disposition: form-data; name="Filedata"; filename="test > video.flv" > Content-Type: application/octet-stream > > ...video content here in junk chars... > ------------cH2Ij5cH2ae0gL6Ef1ae0cH2KM7ae0 > Content-Disposition: form-data; name="Upload" > > Submit Query > ------------cH2Ij5cH2ae0gL6Ef1ae0cH2KM7ae0-- > > It looks like a form submit. My web2py code is this: > > def upload(): > """ > uploads an flv file to server, creates a database entry for it. > """ > db.videodata.insert(flvcopy=db.videodata.flvcopy.store > (request.vars.Filedata,'test1.flv')) > > but this gives me an error I cannot understand. > > Traceback (most recent call last): > File "gluon/restricted.py", line 184, in restricted > File "C:/Home/Software/Development/web2py/applications/videotag/ > controllers/default.py", line 72, in <module> > File "gluon/globals.py", line 102, in <lambda> > File "C:/Home/Software/Development/web2py/applications/videotag/ > controllers/default.py", line 70, in upload > File "gluon/sql.py", line 2357, in store > File "shutil.pyc", line 21, in copyfileobj > File "cgi.pyc", line 548, in __getattr__ > AttributeError: read > > Any help here? > > On Oct 21, 11:45 am, Adi <aditya.sa...@gmail.com> wrote: > > > Tried this once - it stores entire request as text. Trying to figure > > out a way. > > > On Oct 20, 10:14 pm, mdipierro <mdipie...@cs.depaul.edu> wrote: > > > > Sorry, I am not familiar with flash but this is wrong anyway: > > > > return SQLFORM(db.videodata, fields=['flvcopy']).accepts(request.vars, > > > formname=None) > > > > because it should return the form. It would only return True/False > > > from accept > > > > I do not think flex is submitting to a form. I think you may need to > > > do something like > > > > db.table.insert(field=db.table.field.store(request.body,'filename')) > > > > Massimo > > > > On Oct 20, 11:13 am, Adi <aditya.sa...@gmail.com> wrote: > > > > > Any help on this? > > > > > On Oct 20, 12:05 pm, Adi <aditya.sa...@gmail.com> wrote: > > > > > > Hi, > > > > > > I'm developing an application that uses web2py for server and air+flex > > > > > for user interface. Also, I'm a newbie. > > > > > The query is related to this > > > > > post:http://groups.google.com/group/web2py/msg/b1c6d74aead0a401 > > > > > > I'm trying to upload a video file throughFlex. NowFlexwill send the > > > > > request in this format: > > > > > > Content-Type: multipart/form-data; boundary=AaB03x > > > > > --AaB03x > > > > > Content-Disposition: form-data; name="Filedata"; > > > > > filename="example.flv" > > > > > Content-Type: application/octet-stream > > > > > ... contents of example.flv ... > > > > > --AaB03x-- > > > > > > I tried to use this code for upload: > > > > > > def upload(): > > > > > """ > > > > > uploads an flv file to server, creates a database entry for it. > > > > > """ > > > > > # reference:http://bit.ly/remoteupload > > > > > return SQLFORM(db.videodata, fields=['flvcopy']).accepts > > > > > (request.vars, formname=None) > > > > > > where "flvcopy" is the file upload field. However, this is creating a > > > > > new record with all fields as "None" and "flvcopy" having nothing (not > > > > > even None). > > > > > > How do I match my server code to upload the given request? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to web2py@googlegroups.com To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
