looks like need executeSQL needed for string_agg:
Is it possible to do more advanced queries (like using string_agg) with DAL
in the meantime?
Massimo Di Pierro
Apr 12, 2017, 4:21:36 AM
to web...@googlegroups.com
You have to use db.executesql for that. Sorry.
On Saturday, November 14, 2020 at 3:28:06 PM UTC-8 valq...@gmail.com wrote:
> just replace *GROUP_CONCAT* with *string_agg *
>
> воскресенье, 15 ноября 2020 г. в 02:19:52 UTC+3, alexg...@gmail.com:
>
>> I have postgres. How would it look for that?
>>
>> On Saturday, November 14, 2020 at 9:03:13 AM UTC-8 valq...@gmail.com
>> wrote:
>>
>>> Just in case : pydal doesnt support backend specific aggregate functions
>>>
>>>
>>> суббота, 14 ноября 2020 г. в 19:54:35 UTC+3, valq...@gmail.com:
>>>
>>>> There is no db.executesql
>>>>
>>>> суббота, 14 ноября 2020 г. в 19:51:52 UTC+3, alexg...@gmail.com:
>>>>
>>>>> sorry, did not mean direct SQL through db.executesql , meant through
>>>>> DAL
>>>>>
>>>>> On Saturday, November 14, 2020 at 8:23:11 AM UTC-8 valq...@gmail.com
>>>>> wrote:
>>>>>
>>>>>> Assuming sqlite:
>>>>>> person_cnt =
>>>>>> db.PERSON_PROJECT_PRIORITY.person_fk.count().with_alias('person_cnt')
>>>>>>
>>>>>>
>>>>>> prioritySet = db((db.PERSON.id <http://db.person.id/> ==
>>>>>> PERSON-PROJECT-PRIORITY.person_fk) & (PROJECT.id ==
>>>>>> PERSON-PROJECT-PRIORITY.project_fk)).select(
>>>>>> ...,
>>>>>> person_cnt,
>>>>>> 'GROUP_CONCAT(person.person_name,",") AS person_list'
>>>>>> groupby = db.PERSON-PROJECT-PRIORITY.project_fk,
>>>>>> )
>>>>>>
>>>>>> суббота, 14 ноября 2020 г. в 09:40:17 UTC+3, alexg...@gmail.com:
>>>>>>
>>>>>>> How to write a statement that counts which projects are the priority
>>>>>>> of most people
>>>>>>>
>>>>>>> PROJECT
>>>>>>> id
>>>>>>> project_name
>>>>>>>
>>>>>>> PERSON
>>>>>>> id
>>>>>>> person_name
>>>>>>>
>>>>>>> PERSON_PROJECT_PRIORITY
>>>>>>> person_fk
>>>>>>> project_fk
>>>>>>>
>>>>>>> prioritySet = db((db.PERSON.id ==
>>>>>>> PERSON-PROJECT-PRIORITY.person_fk) & (PROJECT.id ==
>>>>>>> PERSON-PROJECT-PRIORITY.project_fk)).select()
>>>>>>>
>>>>>>> How to sort by count of projects which have priority in order of the
>>>>>>> most persons' priority?
>>>>>>>
>>>>>>> Output looks like this:
>>>>>>>
>>>>>>> Paint-the-house (10) [Means is the top priority for 10 people]
>>>>>>> Plant-a-garden (5)
>>>>>>> Clean-out-garage (2)
>>>>>>>
>>>>>>> If you have additional time, how to write so output looks like:
>>>>>>>
>>>>>>> Paint-the-house (10) Tom, Sue, Tony, Ted, Mary, Fred, Sal, Chris,
>>>>>>> Ed, Sally
>>>>>>> Plant-a-garden (5) Harry, George, Joanne, Tony, Janet
>>>>>>> Clean-out-garage (2) Clyde, Jane
>>>>>>>
>>>>>>> Thanks,
>>>>>>>
>>>>>>> Alex Glaros
>>>>>>>
>>>>>>
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