How to write a statement that counts which projects are the priority of most people
PROJECT id project_name PERSON id person_name PERSON_PROJECT_PRIORITY person_fk project_fk prioritySet = db((db.PERSON.id == PERSON-PROJECT-PRIORITY.person_fk) & (PROJECT.id == PERSON-PROJECT-PRIORITY.project_fk)).select() How to sort by count of projects which have priority in order of the most persons' priority? Output looks like this: Paint-the-house (10) [Means is the top priority for 10 people] Plant-a-garden (5) Clean-out-garage (2) If you have additional time, how to write so output looks like: Paint-the-house (10) Tom, Sue, Tony, Ted, Mary, Fred, Sal, Chris, Ed, Sally Plant-a-garden (5) Harry, George, Joanne, Tony, Janet Clean-out-garage (2) Clyde, Jane Thanks, Alex Glaros -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/web2py/493ef6e9-1218-47ee-9498-7b4e185ead70n%40googlegroups.com.
