I do not understand the problem.
On Jul 7, 5:45 pm, pk <peter.kirch...@youngdesigners.de> wrote:
> thanks,
> but if i need the filename from the xml
> because i reed the xml from flex
> and i will show the file in a datagrid
>
> On 8 Jul., 00:36, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
> > assuming
>
> > db.define_table('mytable',Field('myimage','upload'))
>
> > and a controller
>
> > def download(): return response.download(request,db)
>
> > than the URL is
>
> > http://hostname:port/[app]/[controller]/download/[filename]
>
> > and filename is the one stored in db.mytable.myimage, not the original
> > filename.
>
> > Massimo
>
> > On Jul 7, 5:12 pm, pk <peter.kirch...@youngdesigners.de> wrote:
>
> > > hi,
> > > how can i access to the url of a image which i load up in the table.
> > > because i have another application (not web2py) and read the table
> > > with xml.
> > > now i need to access to the file.
> > > thanks
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