thanks,
but if i need the filename from the xml
because i reed the xml from flex
and i will show the file in a datagrid
On 8 Jul., 00:36, mdipierro <mdipie...@cs.depaul.edu> wrote:
> assuming
>
> db.define_table('mytable',Field('myimage','upload'))
>
> and a controller
>
> def download(): return response.download(request,db)
>
> than the URL is
>
> http://hostname:port/[app]/[controller]/download/[filename]
>
> and filename is the one stored in db.mytable.myimage, not the original
> filename.
>
> Massimo
>
> On Jul 7, 5:12 pm, pk <peter.kirch...@youngdesigners.de> wrote:
>
> > hi,
> > how can i access to the url of a image which i load up in the table.
> > because i have another application (not web2py) and read the table
> > with xml.
> > now i need to access to the file.
> > thanks
>
>
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