Ah I see now, Thanks.
On Tue, Jun 25, 2013 at 1:31 PM, Anthony <abasta...@gmail.com> wrote:
> If you only provide two positional args to URL, it assumes they are the
> controller and function. In this case, you'll need to specify the
> application, controller, and function:
>
> URL("AppointmentManager", "yourcontroller", "appointment_create", args=[
> row.id])
>
> You can also used keyword arguments "a", "c", and "f" with URL().
>
> Anthony
>
> On Tuesday, June 25, 2013 12:08:57 PM UTC-4, Tom Russell wrote:
>>
>> I have a smartgrid with a link like so:
>>
>> links = [lambda row: A(T('Create Appointment'),_href=URL("**
>> AppointmentManager","**appointment_create",args=[row.**id <http://row.id>
>> ]))]
>>
>> grid = SQLFORM.smartgrid(db.patient, deletable=True, editable=True,
>> create=True, maxtextlength=64, paginate=25, links=links,
>> links_in_grid=True, linked_tables=['**emergencycontacts','**
>> dependents'])
>> return dict(grid=grid)
>>
>> Problem is that AppointmentManager is another app and the url points to
>> /currentapp/**AppointmentManager/ etc, so how do I have it redirect to
>> the other app?
>>
>> I looked in the book but could'nt find this.
>>
>> Thanks
>>
>> Tom
>>
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