I have a smartgrid with a link like so:
links = [lambda row: A(T('Create
Appointment'),_href=URL("AppointmentManager","appointment_create",args=[
row.id]))]
grid = SQLFORM.smartgrid(db.patient, deletable=True, editable=True,
create=True, maxtextlength=64, paginate=25, links=links,
links_in_grid=True, linked_tables=['emergencycontacts','dependents'])
return dict(grid=grid)
Problem is that AppointmentManager is another app and the url points to
/currentapp/AppointmentManager/ etc, so how do I have it redirect to the
other app?
I looked in the book but could'nt find this.
Thanks
Tom
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