On Mon, Apr 15, 2013 at 3:24 PM, James Bowery <[email protected]> wrote:
That means he has a whopping 512kJ to run down during his 5 hours. This > calculates out to: > > 512kJ;5hour?W > (512 * [kilo*joule]) * (5 * hour)^-1 ? watt > = 28.444444 W > > That's just about enough to run a little fan. > According to this link, a ceiling fan running at low speed consumes 24 W [1]. I have not seen the magnet motor video, but assuming the fan is smaller and has less mass than a celling fan, I think we can scale down the power consumed linearly using the ratio of the estimated masses of the two fans. Eric [1] http://www.heraldextra.com/amount-of-electricity-consumed-by-common-small-appliances/article_ee000c18-5cec-11de-ac79-001cc4c03286.html
