In reply to [email protected]'s message of Wed, 15 Aug 2012 14:54:29 -0400 (EDT): Hi, [snip] >"Brillouin's lattice stimulation reverses the natural decay of neutrons to >protons and Beta particles, catalyzing this endothermic step. Constraining >a proton spatially in a lattice causes the lattice energy to be highly >uncertain. With the Hamiltonian of the system reaching 782KeV for a proton >or 3MeV for a deuteron the system may be capable of capturing an electron, >forming an ultra-cold neutron or di-neutron system."
If I understand this correctly, it would require an uncertainty in position of less than 2.7 fm (comparable in magnitude to the size of a nucleus) for a proton, and < 1.3 fm for a deuteron. Note that the latter is less than the size of the deuteron itself. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
