I expect the following to output 1 (be equal), but its not. I don't understand
why
echo substitute("-D abc\nfoo/bar\n-L x", "-[DL][ ]*[^\n]*",'','g')
\ == substitute("-D abc\nfoo/bar\n-L x", '-[DL][ ]*[^\n]*','','g')
Why do I expect so ? because "[\n]" should be the same as '[\n]' - however
'[\n]' should be replaced by chr(10) by the pattern interpreter according to
help:
according to :h pattern.txt /A collection. This is a sequence of characters
enclosed in brackets
- The following translations are accepted when the 'l' flag is not
included in 'cpoptions' {not in Vi}:
[..]
\n line break, see above |/[\n]|
Which piece am I missunderstanding?
Marc Weber
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