On Tue Nov 14 01:46:09 2023 "Thomas Hoffmann (Speed4Trade GmbH)"
<thomas.hoffm...@speed4trade.com.INVALID> wrote:
>
> Hello Mark,
>
> > -----Ursprüngliche Nachricht-----
> > Von: Mark Foley <mfo...@novatec-inc.com>
> > Gesendet: Montag, 13. November 2023 23:12
> > An: users@tomcat.apache.org
> > Betreff: Re: AW: FileUpload class not working with Tomcat 10.1
> >
> > On Mon Nov 13 02:18:49 2023 "Thomas Hoffmann (Speed4Trade GmbH)"
> > <thomas.hoffm...@speed4trade.com.INVALID> wrote:
> > > Hello,
> > >
> > > > -----Ursprüngliche Nachricht-----
> > > > Von: Mark Foley <mfo...@novatec-inc.com>
> > > > Gesendet: Sonntag, 12. November 2023 19:04
> > > > An: users@tomcat.apache.org
> > > > Betreff: Re: FileUpload class not working with Tomcat 10.1
> > > >
> > > > On Fri Nov 10 15:57:50 2023 Christopher Schultz
> > > > <ch...@christopherschultz.net> wrote:
> > > > >
> > > > > Mark,
> > > > >
> > > > > On 11/10/23 12:53, Mark Foley wrote:
> > > > > > On Fri, 10 Nov 2023 17:11:59 Mark Thomas <ma...@apache.org
> > wrote:
> > > > > >>
> > > > > >> On 10/11/2023 16:49, Mark Foley wrote:
> > > > > >>> I recently upgraded from Tomcat 10.0.17 to 10.1.13. ...
> > > > > >>>
> > > > > >>> [deleted]
> > > > >
> > > > I've put your suggested code in place.
> > > >
> > > > <%@ page import="jakarta.servlet.http.Part" %>
> > > >
> > > > I replaced your:
> > > >
> > > > throw new IllegalStateException("Expected multi-part");
> > > >
> > > > with:
> > > >
> > > > out.println("Expected multi-part");
> > > >
> > > > Just to get things compiling OK. I'll deal with errors later. With
> > > > that change, it compiled w/o problem. I then attempted an upload. The
> > line:
> > > >
> > > > if(null == contentType ||
> > > > !contentType.startsWith("multipart/form-data;"))
> > > > {
> > > >
> > > > returned TRUE so it did detect a multipart upload. Yay! That was a
> > > > relief However
> > > >
> > > > Part fileUpload = request.getPart("param-name");
> > > >
> > > > Gave me the error:
> > > >
> > > > java.lang.IllegalStateException: Unable to process parts as no
> > > > multi-part configuration has been provided
> > > >
> > > > So, what does it mean that "no multi-part configuration has been
> > provided"?
> > > > Is "param-name" something I'm supposed to fill in? I tried
> > > > substituting the <input type="file"> field name, "taxResults", but that
> > gave the same error.
> > >
> > > The form element must have the attribute enctype="multipart/form-
> > data".
> > > Furthermore, the servlet must be annotated by "@MultipartConfig"
> > >
> > > I think for jsp files, there is a similar setting in the web.xml.
> > > This link might help out:
> > > https://stackoverflow.com/questions/37965890/add-annotation-to-jsp
> >
> > Thanks for your reply Thomas.
> >
> > I've checked your suggested link and I have no idea where to put all that
> > <?xml> stuff. Furthermore, the poster of that issue didn't say he got it
> > working.
> >
> > A respnder to the post said, "Actually every jsp file will be converted to
> > servlet because tomcat can only address servlet and so every jsp file is
> > indirectly a servlet and has all the features of it". I think he is
> > suggesting that
> > the <?xml> code is superfluous, but not exlpicitly stated as such.
> >
> > I am getting a TRUE return for
> >
> > if(null == contentType || !contentType.startsWith("multipart/form-data;"))
> >
> > so I think it is recognizing it as "multipart/form-data;".
> >
> > Does anyone have an example of a JSP program with
> > jakarta.servlet.http.Part class?
> >
> > I'll search for examples as well, but I really have no idea how to proceed.
> >
> > --Mark F.
> >
>
> The servlet specification defines the special folder WEB-INF.
> Within this folder, there is the configuration file named web.xml.
> Within this xml-File, the application is configured including the servlets.
> JSP-Files are compiled to servlets, either on-the-fly or during compilation
> time.
>
> I would recommend to take a look at some sample applications to get familiar
> with some java web-applications and the web.xml file.
>
> It is not only about the jsp-file but also the combination with the
> application configuration within the web.xml
> Thus you will need both, jsp-file and a corresponding web.xml configuration.
>
> Greetings!
> Thomas
Thomas, I would LOVE to find some examples on this application! I've spent days
searching and mostly I've found examples for pre 10.1 Tomcat, including numerous
examples of the type Christopher Schultz found "horrifying". Christopher
Schultz's suggested example imported "jakarta.servlet.http.Part", but your link
example doesn't mention that class and instead imports
"javax.servlet.annotation.MultipartConfig".
As I said, an actual working example somewhere would be nice.
I've used WEB-INF/web.xml for several context definitions, so I am familiar with
it, but have never configured a servlet in web.xml.
Anyway, enough griping! I have gotten it partially working thanks to your
suggested link, and particulary you suggestion to put the servlet info in
web.xml. I've put the following in WEB-INF/web.xml:
<servlet>
<servlet-name>uploadfile</servlet-name>
<jsp-file>/schDistImportResultsX.jsp</jsp-file>
<multipart-config>
<location>/tmp</location>
<max-file-size>20848820</max-file-size>
<max-request-size>418018841</max-request-size>
<file-size-threshold>1048576</file-size-threshold>
</multipart-config>
</servlet>
<servlet-mapping>
<servlet-name>uploadfile</servlet-name>
<url-pattern>/schDistImportResultsX.jsp</url-pattern>
</servlet-mapping>
I've only changed the <jsp-file> and <url-pattern> tags above. The others are
as monkey-typed from your link example. I'll research the other parameters
later.
My jsp code is now:
<%@ page import="javax.servlet.annotation.MultipartConfig.*" %>
if((contentType != null) && contentType.startsWith("multipart/form-data;"))
{
InputStream inp = null;
DataInputStream ins = null;
Part fileUpload = request.getPart("taxResults");
if(fileUpload != null)
{
inp = fileUpload.getInputStream();
ins = new DataInputStream(inp);
}
while ((inp != null) && (ins.available() != 0))
{
String transaction = ins.readLine();
out.println("<br/>" + transaction);
}
ins.close();
inp.close();
This actually worked!!!! I will experiment with it more and may be back with
more questions (e.g. do I really need the web.xml? Could I not do:
"inp = fileUpload.getInputStream(mypath);"). But ... maybe later.
Vielen Dank!!! --Mark
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