Hello Mark,
> -----Ursprüngliche Nachricht-----
> Von: Mark Foley <mfo...@novatec-inc.com>
> Gesendet: Montag, 13. November 2023 23:12
> An: users@tomcat.apache.org
> Betreff: Re: AW: FileUpload class not working with Tomcat 10.1
>
> On Mon Nov 13 02:18:49 2023 "Thomas Hoffmann (Speed4Trade GmbH)"
> <thomas.hoffm...@speed4trade.com.INVALID> wrote:
> > Hello,
> >
> > > -----Ursprüngliche Nachricht-----
> > > Von: Mark Foley <mfo...@novatec-inc.com>
> > > Gesendet: Sonntag, 12. November 2023 19:04
> > > An: users@tomcat.apache.org
> > > Betreff: Re: FileUpload class not working with Tomcat 10.1
> > >
> > > On Fri Nov 10 15:57:50 2023 Christopher Schultz
> > > <ch...@christopherschultz.net> wrote:
> > > >
> > > > Mark,
> > > >
> > > > On 11/10/23 12:53, Mark Foley wrote:
> > > > > On Fri, 10 Nov 2023 17:11:59 Mark Thomas <ma...@apache.org
> wrote:
> > > > >>
> > > > >> On 10/11/2023 16:49, Mark Foley wrote:
> > > > >>> I recently upgraded from Tomcat 10.0.17 to 10.1.13. ...
> > > > >>>
> > > > >>> [deleted]
> > > >
> > > I've put your suggested code in place.
> > >
> > > <%@ page import="jakarta.servlet.http.Part" %>
> > >
> > > I replaced your:
> > >
> > > throw new IllegalStateException("Expected multi-part");
> > >
> > > with:
> > >
> > > out.println("Expected multi-part");
> > >
> > > Just to get things compiling OK. I'll deal with errors later. With
> > > that change, it compiled w/o problem. I then attempted an upload. The
> line:
> > >
> > > if(null == contentType ||
> > > !contentType.startsWith("multipart/form-data;"))
> > > {
> > >
> > > returned TRUE so it did detect a multipart upload. Yay! That was a
> > > relief However
> > >
> > > Part fileUpload = request.getPart("param-name");
> > >
> > > Gave me the error:
> > >
> > > java.lang.IllegalStateException: Unable to process parts as no
> > > multi-part configuration has been provided
> > >
> > > So, what does it mean that "no multi-part configuration has been
> provided"?
> > > Is "param-name" something I'm supposed to fill in? I tried
> > > substituting the <input type="file"> field name, "taxResults", but that
> gave the same error.
> >
> > The form element must have the attribute enctype="multipart/form-
> data".
> > Furthermore, the servlet must be annotated by "@MultipartConfig"
> >
> > I think for jsp files, there is a similar setting in the web.xml.
> > This link might help out:
> > https://stackoverflow.com/questions/37965890/add-annotation-to-jsp
>
> Thanks for your reply Thomas.
>
> I've checked your suggested link and I have no idea where to put all that
> <?xml> stuff. Furthermore, the poster of that issue didn't say he got it
> working.
>
> A respnder to the post said, "Actually every jsp file will be converted to
> servlet because tomcat can only address servlet and so every jsp file is
> indirectly a servlet and has all the features of it". I think he is
> suggesting that
> the <?xml> code is superfluous, but not exlpicitly stated as such.
>
> I am getting a TRUE return for
>
> if(null == contentType || !contentType.startsWith("multipart/form-data;"))
>
> so I think it is recognizing it as "multipart/form-data;".
>
> Does anyone have an example of a JSP program with
> jakarta.servlet.http.Part class?
>
> I'll search for examples as well, but I really have no idea how to proceed.
>
> --Mark F.
>
The servlet specification defines the special folder WEB-INF.
Within this folder, there is the configuration file named web.xml.
Within this xml-File, the application is configured including the servlets.
JSP-Files are compiled to servlets, either on-the-fly or during compilation
time.
I would recommend to take a look at some sample applications to get familiar
with some java web-applications and the web.xml file.
It is not only about the jsp-file but also the combination with the application
configuration within the web.xml
Thus you will need both, jsp-file and a corresponding web.xml configuration.
Greetings!
Thomas
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