Re: regex: chars to escape bsides @

[Reindl Harald]

Am 05.01.2015 um 19:14 schrieb Bowie Bailey:

On 1/4/2015 5:42 AM, Reindl Harald wrote:

Am 04.01.2015 um 06:43 schrieb Bob Proulx:

The additional issue was that you were referencing PHP documentation.
Might as well have been referencing Lisp documentation for all of the
relevance it had. That was the point I saw being addressed at that
point. PHP is a similar syntax that came after Perl but it very much
is its own thing and Perl does not derive from it

we are talking about PCRE and the PHP function preg_quote() to escape
a string for *perl* regular expressions not the language syntax and
since the backneds are alreay there i just asked *what* chars
*additional* to that function needs to be escaped *besides* the @ i
found out myself

that is a short and simple question and not refer to the used PHP
function would not have been hepful at all

Ok.  Here is an attempt at a simple answer off the top of my head. (Not
guaranteed to be complete)

The following characters may need to be escaped in a Perl regex (as used
in SA) if intended to be used as literal characters:

$%@/[{*+?\

] and } may need to be escaped as well, but I don't think it is required.

You can avoid having to escape the slash (/) by using a different
separator for the regex.  This can avoid "leaning toothpick syndrome."

[harry@srv-rhsoft:/downloads]$ cat test.php
#!/usr/bin/php
<?php
 $chars = '$ % @ / [ ] { } \ * + ? ! \\';
 echo $chars . "\n";
 echo preg_quote($chars) . "\n";
 echo sa_quote($chars) . "\n";
 function sa_quote($input)
 {
  $input = str_replace(array("\n", "\r", "\0"), '', trim($input));
  $input = str_replace("\t", ' ', $input);
  $input = preg_quote($input);
  $input = str_replace('/', '\/', $input);
  $input = str_replace('@', '\@', $input);
  $input = str_replace('%', '\%', $input);
  return $input;
 }
?>

[harry@srv-rhsoft:/downloads]$ ./test.php
$ % @ / [ ] { } \ * + ? ! \
\$ % @ / \[ \] \{ \} \\ \* \+ \? \! \\
\$ \% \@ \/ \[ \] \{ \} \\ \* \+ \? \! \\

thanks, i ended last night in the wrapper-function below while / already got escaped since this is also needed for postfix header_checks so finally there was only % missing i got aware on that thread, @ was already handeled after taking notice and the rest is done properly by preg_quote()

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