My concern is how do the C side know fortran integer using 8 bytes?
My valgrind check show something like:
==8482== Invalid read of size 8
==8482== at 0x5F4A50E: ompi_op_base_minloc_2integer (op_base_functions.c:631)
==8482== by 0xBF70DD1: ompi_coll_tuned_allreduce_intra_recursivedoubling
(op.h:498)
==8482== by 0x5F031CB: PMPI_Allreduce (pallreduce.c:105)
==8482== by 0x62E2F22: PMPI_ALLREDUCE (pallreduce_f.c:77)
==8482== by 0x5C8934: mumps_276_ (mumps_part9.F:4667)
==8482== by 0x54D89A: dmumps_ (dmumps_part1.F:157)
==8482== by 0x43D358: dmumps_f77_ (dmumps_part3.F:6651)
==8482== by 0x41420C: dmumps_c (mumps_c.c:422)
==8482== by 0x412CB4: main (my_cExample_client.c:80)
==8482== Address 0x7369608 is 0 bytes after a block of size 8 alloc'd
==8482== at 0x4A0610C: malloc (vg_replace_malloc.c:195)
==8482== by 0xBF709B9: ompi_coll_tuned_allreduce_intra_recursivedoubling
(coll_tuned_allreduce.c:158)
==8482== by 0x5F031CB: PMPI_Allreduce (pallreduce.c:105)
==8482== by 0x62E2F22: PMPI_ALLREDUCE (pallreduce_f.c:77)
==8482== by 0x5C8934: mumps_276_ (mumps_part9.F:4667)
==8482== by 0x54D89A: dmumps_ (dmumps_part1.F:157)
==8482== by 0x43D358: dmumps_f77_ (dmumps_part3.F:6651)
==8482== by 0x41420C: dmumps_c (mumps_c.c:422)
==8482== by 0x412CB4: main (my_cExample_client.c:80)
The fortran side:
INTEGER IN( 2 ), OUT( 2 )
CALL MPI_ALLREDUCE( IN, OUT, 1, MPI_2INTEGER, MPI_MINLOC,
& COMM, IERR)
The compiler options will take care of IN be INTEGER*8, but will
it do the same for MPI_2INTEGER in the C side
Thanks.
Regards,
William
List-Post: users@lists.open-mpi.org
Date: Fri, 29 Jun 2012 07:03:18 -0400
From: Jeff Squyres <jsquy...@cisco.com>
Subject: Re: [OMPI users] fortran program with integer kind=8 using
openmpi
To: <war...@atmos.washington.edu>, Open MPI Users <us...@open-mpi.org>
Message-ID: <6ffea644-3f39-4b6e-add6-3721f4855...@cisco.com>
Content-Type: text/plain; charset=iso-8859-1
On Jun 28, 2012, at 8:37 PM, David Warren wrote:
> You should not have to recompile openmpi, but you do have to use the correct
> type. You can check the size of integers in your fortrana nd use MPI_INTEGER4
> or MPI_INTEGER8 depending on what you get.
If you configure ompi with -fdefault-integer-8, then OMPI will assume that
Fortran integers are always 8 bytes, so be sure to also compile all of your MPI
applications the same way. Indeed, you may want to configure OMPI with
something like:
./configure FCFLAGS=-fdefault-integer-8 FFLAGS=-fdefault-integer-8 \
--with-wrapper-fflags=-fdefault-integer-8 \
--with-wrapper-fcflags=-fdefault-integer-8
This will add -fdefault-integer-8 to the mpif77 and mpif90 command lines
automatically so that you *can't* compile without that flag.
Be aware that 8-byte Fortran integers *should work* in Open MPI, but it is
probably not well tested. You may well run into some issues; be sure to let us
know if you run into bugs. Sending small test programs that show the problem
are usually the best way to help us identify/fix the precise problem.
> in gfortran use
> integer i
> if(sizeof(i) .eq. 8) then
> mpi_int_type=MPI_INTEGER8
> else
> mpi_int_type=MPI_INTEGER4
> endif
I don't think that this should be necessary -- as long as you configured OMPI
with the 8-byte-integer setting, then MPI_INTEGER should represent an 8 byte
integer.
--
Jeff Squyres
jsquy...@cisco.com
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