> What is the meaning of parameters sms-center and my-number for smsc =
> at? I can send sms from phone without them. Why I need to know it for
> sending sms via kannel from the same sim card? How can I know them?

I have found values for this parameters, so my configuration is looks like:

group = smsc
smsc = at
smsc-id = smsc-0
modemtype = huawei
device = /dev/ttyUSB1
sms-center = "+7123456789"
my-number = "+7987654321"
pin = 0000

group = modems
id = modem-0
detect-string = "huawei"
init-string = "ATQ0 V1 E1 S0=0 &C1 &D2 +FCLASS=0"

I have run bearerbox and see:

2012-09-11 15:34:16 [5608] [6] INFO: AT2[smsc-0]: init device
2012-09-11 15:34:16 [5608] [6] INFO: AT2[smsc-0]: speed set to 115200
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: --> ATZ^M
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: <-- OK
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: --> AT^M
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: <-- AT
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: <-- OK
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: --> AT&F^M
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: <-- AT&F
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: <-- OK
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: --> ATE0^M
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: <-- ATE0
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: <-- OK
2012-09-11 15:34:16 [5608] [6] DEBUG: AT2[smsc-0]: --> AT+IFC=2,2^M
2012-09-11 15:34:17 [5608] [6] DEBUG: AT2[smsc-0]: <-- OK
2012-09-11 15:34:17 [5608] [6] DEBUG: AT2[smsc-0]: --> AT+CPIN?^M
2012-09-11 15:34:17 [5608] [6] DEBUG: AT2[smsc-0]: <-- +CPIN: READY
2012-09-11 15:34:17 [5608] [6] DEBUG: AT2[smsc-0]: --> AT+CSCA="+7123456789"^M
2012-09-11 15:34:17 [5608] [6] DEBUG: AT2[smsc-0]: <-- OK
2012-09-11 15:34:17 [5608] [6] DEBUG: AT2[smsc-0]: --> AT+CMGF=0^M
2012-09-11 15:34:17 [5608] [6] DEBUG: AT2[smsc-0]: <-- ERROR
2012-09-11 15:34:17 [5608] [6] ERROR: AT2[smsc-0]: Generic error: ERROR

AT+CMGF=0 is looks like swiching to PDU mode,
so why can it be a problem?

--
Regards,
Eugene Prokopiev

Reply via email to