You were right first time ....
if you use a reference, then there is no copy created when you do the
call; and then you build up the output list.
without the reference, there is an initial copy and then you
additionally build the output list.
So using a reference parameter saves the memory for one copy (plus the
cpu to create the copy).
-- Alex.
On 16/02/2015 23:06, Peter M. Brigham wrote:
I wrote:
I referenced the list and turned the function into a command, saves memory
(possibly speed?) on very large lists.
I just realized that no memory is saved this way because we are building a new
duplicate (reversed) list within the command. So referencing the list has no
advantage.
-- Peter
Peter M. Brigham
pmb...@gmail.com
http://home.comcast.net/~pmbrig
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